Integrand size = 18, antiderivative size = 133 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^3} \, dx=\frac {5}{4} b (3 A b+4 a B) \sqrt {a+b x}+\frac {5 b (3 A b+4 a B) (a+b x)^{3/2}}{12 a}-\frac {(3 A b+4 a B) (a+b x)^{5/2}}{4 a x}-\frac {A (a+b x)^{7/2}}{2 a x^2}-\frac {5}{4} \sqrt {a} b (3 A b+4 a B) \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right ) \]
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Time = 0.04 (sec) , antiderivative size = 133, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.278, Rules used = {79, 43, 52, 65, 214} \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^3} \, dx=-\frac {5}{4} \sqrt {a} b (4 a B+3 A b) \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )-\frac {(a+b x)^{5/2} (4 a B+3 A b)}{4 a x}+\frac {5 b (a+b x)^{3/2} (4 a B+3 A b)}{12 a}+\frac {5}{4} b \sqrt {a+b x} (4 a B+3 A b)-\frac {A (a+b x)^{7/2}}{2 a x^2} \]
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Rule 43
Rule 52
Rule 65
Rule 79
Rule 214
Rubi steps \begin{align*} \text {integral}& = -\frac {A (a+b x)^{7/2}}{2 a x^2}+\frac {\left (\frac {3 A b}{2}+2 a B\right ) \int \frac {(a+b x)^{5/2}}{x^2} \, dx}{2 a} \\ & = -\frac {(3 A b+4 a B) (a+b x)^{5/2}}{4 a x}-\frac {A (a+b x)^{7/2}}{2 a x^2}+\frac {(5 b (3 A b+4 a B)) \int \frac {(a+b x)^{3/2}}{x} \, dx}{8 a} \\ & = \frac {5 b (3 A b+4 a B) (a+b x)^{3/2}}{12 a}-\frac {(3 A b+4 a B) (a+b x)^{5/2}}{4 a x}-\frac {A (a+b x)^{7/2}}{2 a x^2}+\frac {1}{8} (5 b (3 A b+4 a B)) \int \frac {\sqrt {a+b x}}{x} \, dx \\ & = \frac {5}{4} b (3 A b+4 a B) \sqrt {a+b x}+\frac {5 b (3 A b+4 a B) (a+b x)^{3/2}}{12 a}-\frac {(3 A b+4 a B) (a+b x)^{5/2}}{4 a x}-\frac {A (a+b x)^{7/2}}{2 a x^2}+\frac {1}{8} (5 a b (3 A b+4 a B)) \int \frac {1}{x \sqrt {a+b x}} \, dx \\ & = \frac {5}{4} b (3 A b+4 a B) \sqrt {a+b x}+\frac {5 b (3 A b+4 a B) (a+b x)^{3/2}}{12 a}-\frac {(3 A b+4 a B) (a+b x)^{5/2}}{4 a x}-\frac {A (a+b x)^{7/2}}{2 a x^2}+\frac {1}{4} (5 a (3 A b+4 a B)) \text {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b x}\right ) \\ & = \frac {5}{4} b (3 A b+4 a B) \sqrt {a+b x}+\frac {5 b (3 A b+4 a B) (a+b x)^{3/2}}{12 a}-\frac {(3 A b+4 a B) (a+b x)^{5/2}}{4 a x}-\frac {A (a+b x)^{7/2}}{2 a x^2}-\frac {5}{4} \sqrt {a} b (3 A b+4 a B) \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right ) \\ \end{align*}
Time = 0.18 (sec) , antiderivative size = 91, normalized size of antiderivative = 0.68 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^3} \, dx=\frac {\sqrt {a+b x} \left (8 b^2 x^2 (3 A+B x)-6 a^2 (A+2 B x)+a b x (-27 A+56 B x)\right )}{12 x^2}-\frac {5}{4} \sqrt {a} b (3 A b+4 a B) \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right ) \]
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Time = 0.53 (sec) , antiderivative size = 87, normalized size of antiderivative = 0.65
method | result | size |
pseudoelliptic | \(\frac {-\frac {15 x^{2} b \left (A b +\frac {4 B a}{3}\right ) a \,\operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{4}+2 \sqrt {b x +a}\, \left (-\frac {9 x b \left (-\frac {56 B x}{27}+A \right ) a^{\frac {3}{2}}}{8}+\left (-\frac {B x}{2}-\frac {A}{4}\right ) a^{\frac {5}{2}}+b^{2} x^{2} \sqrt {a}\, \left (\frac {B x}{3}+A \right )\right )}{x^{2} \sqrt {a}}\) | \(87\) |
risch | \(-\frac {a \sqrt {b x +a}\, \left (9 A b x +4 B a x +2 A a \right )}{4 x^{2}}+\frac {b \left (\frac {16 B \left (b x +a \right )^{\frac {3}{2}}}{3}+16 A b \sqrt {b x +a}+32 B a \sqrt {b x +a}-10 \sqrt {a}\, \left (3 A b +4 B a \right ) \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )\right )}{8}\) | \(92\) |
derivativedivides | \(2 b \left (\frac {B \left (b x +a \right )^{\frac {3}{2}}}{3}+A b \sqrt {b x +a}+2 B a \sqrt {b x +a}-a \left (\frac {\left (\frac {9 A b}{8}+\frac {B a}{2}\right ) \left (b x +a \right )^{\frac {3}{2}}+\left (-\frac {7}{8} a b A -\frac {1}{2} a^{2} B \right ) \sqrt {b x +a}}{b^{2} x^{2}}+\frac {5 \left (3 A b +4 B a \right ) \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{8 \sqrt {a}}\right )\right )\) | \(111\) |
default | \(2 b \left (\frac {B \left (b x +a \right )^{\frac {3}{2}}}{3}+A b \sqrt {b x +a}+2 B a \sqrt {b x +a}-a \left (\frac {\left (\frac {9 A b}{8}+\frac {B a}{2}\right ) \left (b x +a \right )^{\frac {3}{2}}+\left (-\frac {7}{8} a b A -\frac {1}{2} a^{2} B \right ) \sqrt {b x +a}}{b^{2} x^{2}}+\frac {5 \left (3 A b +4 B a \right ) \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{8 \sqrt {a}}\right )\right )\) | \(111\) |
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Time = 0.23 (sec) , antiderivative size = 209, normalized size of antiderivative = 1.57 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^3} \, dx=\left [\frac {15 \, {\left (4 \, B a b + 3 \, A b^{2}\right )} \sqrt {a} x^{2} \log \left (\frac {b x - 2 \, \sqrt {b x + a} \sqrt {a} + 2 \, a}{x}\right ) + 2 \, {\left (8 \, B b^{2} x^{3} - 6 \, A a^{2} + 8 \, {\left (7 \, B a b + 3 \, A b^{2}\right )} x^{2} - 3 \, {\left (4 \, B a^{2} + 9 \, A a b\right )} x\right )} \sqrt {b x + a}}{24 \, x^{2}}, \frac {15 \, {\left (4 \, B a b + 3 \, A b^{2}\right )} \sqrt {-a} x^{2} \arctan \left (\frac {\sqrt {b x + a} \sqrt {-a}}{a}\right ) + {\left (8 \, B b^{2} x^{3} - 6 \, A a^{2} + 8 \, {\left (7 \, B a b + 3 \, A b^{2}\right )} x^{2} - 3 \, {\left (4 \, B a^{2} + 9 \, A a b\right )} x\right )} \sqrt {b x + a}}{12 \, x^{2}}\right ] \]
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Time = 36.70 (sec) , antiderivative size = 316, normalized size of antiderivative = 2.38 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^3} \, dx=- \frac {7 A \sqrt {a} b^{2} \operatorname {asinh}{\left (\frac {\sqrt {a}}{\sqrt {b} \sqrt {x}} \right )}}{4} - \frac {A a^{3}}{2 \sqrt {b} x^{\frac {5}{2}} \sqrt {\frac {a}{b x} + 1}} - \frac {3 A a^{2} \sqrt {b}}{4 x^{\frac {3}{2}} \sqrt {\frac {a}{b x} + 1}} - \frac {2 A a b^{\frac {3}{2}} \sqrt {\frac {a}{b x} + 1}}{\sqrt {x}} - \frac {A a b^{\frac {3}{2}}}{4 \sqrt {x} \sqrt {\frac {a}{b x} + 1}} + A b^{2} \left (\begin {cases} \frac {2 a \operatorname {atan}{\left (\frac {\sqrt {a + b x}}{\sqrt {- a}} \right )}}{\sqrt {- a}} + 2 \sqrt {a + b x} & \text {for}\: b \neq 0 \\\sqrt {a} \log {\left (x \right )} & \text {otherwise} \end {cases}\right ) - B a^{\frac {3}{2}} b \operatorname {asinh}{\left (\frac {\sqrt {a}}{\sqrt {b} \sqrt {x}} \right )} - \frac {B a^{2} \sqrt {b} \sqrt {\frac {a}{b x} + 1}}{\sqrt {x}} + 2 B a b \left (\begin {cases} \frac {2 a \operatorname {atan}{\left (\frac {\sqrt {a + b x}}{\sqrt {- a}} \right )}}{\sqrt {- a}} + 2 \sqrt {a + b x} & \text {for}\: b \neq 0 \\\sqrt {a} \log {\left (x \right )} & \text {otherwise} \end {cases}\right ) + B b^{2} \left (\begin {cases} \frac {2 \left (a + b x\right )^{\frac {3}{2}}}{3 b} & \text {for}\: b \neq 0 \\\sqrt {a} x & \text {otherwise} \end {cases}\right ) \]
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Time = 0.28 (sec) , antiderivative size = 155, normalized size of antiderivative = 1.17 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^3} \, dx=\frac {1}{24} \, {\left (\frac {15 \, {\left (4 \, B a + 3 \, A b\right )} \sqrt {a} \log \left (\frac {\sqrt {b x + a} - \sqrt {a}}{\sqrt {b x + a} + \sqrt {a}}\right )}{b} - \frac {6 \, {\left ({\left (4 \, B a^{2} + 9 \, A a b\right )} {\left (b x + a\right )}^{\frac {3}{2}} - {\left (4 \, B a^{3} + 7 \, A a^{2} b\right )} \sqrt {b x + a}\right )}}{{\left (b x + a\right )}^{2} b - 2 \, {\left (b x + a\right )} a b + a^{2} b} + \frac {16 \, {\left ({\left (b x + a\right )}^{\frac {3}{2}} B + 3 \, {\left (2 \, B a + A b\right )} \sqrt {b x + a}\right )}}{b}\right )} b^{2} \]
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Time = 0.28 (sec) , antiderivative size = 155, normalized size of antiderivative = 1.17 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^3} \, dx=\frac {8 \, {\left (b x + a\right )}^{\frac {3}{2}} B b^{2} + 48 \, \sqrt {b x + a} B a b^{2} + 24 \, \sqrt {b x + a} A b^{3} + \frac {15 \, {\left (4 \, B a^{2} b^{2} + 3 \, A a b^{3}\right )} \arctan \left (\frac {\sqrt {b x + a}}{\sqrt {-a}}\right )}{\sqrt {-a}} - \frac {3 \, {\left (4 \, {\left (b x + a\right )}^{\frac {3}{2}} B a^{2} b^{2} - 4 \, \sqrt {b x + a} B a^{3} b^{2} + 9 \, {\left (b x + a\right )}^{\frac {3}{2}} A a b^{3} - 7 \, \sqrt {b x + a} A a^{2} b^{3}\right )}}{b^{2} x^{2}}}{12 \, b} \]
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Time = 0.44 (sec) , antiderivative size = 162, normalized size of antiderivative = 1.22 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^3} \, dx=\left (2\,A\,b^2+4\,B\,a\,b\right )\,\sqrt {a+b\,x}-\frac {\left (B\,a^2\,b+\frac {9\,A\,a\,b^2}{4}\right )\,{\left (a+b\,x\right )}^{3/2}-\left (B\,a^3\,b+\frac {7\,A\,a^2\,b^2}{4}\right )\,\sqrt {a+b\,x}}{{\left (a+b\,x\right )}^2-2\,a\,\left (a+b\,x\right )+a^2}+\frac {2\,B\,b\,{\left (a+b\,x\right )}^{3/2}}{3}+2\,b\,\mathrm {atan}\left (\frac {2\,b\,\left (3\,A\,b+4\,B\,a\right )\,\sqrt {-\frac {25\,a}{64}}\,\sqrt {a+b\,x}}{5\,B\,a^2\,b+\frac {15\,A\,a\,b^2}{4}}\right )\,\left (3\,A\,b+4\,B\,a\right )\,\sqrt {-\frac {25\,a}{64}} \]
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